Unmarshal in Go

Posted by GoDoc
Public (Editable by Users)

This example demonstrates unmarshaling an XML excerpt into a value with some preset fields. Note that the Phone field isn't modified and that the XML element is ignored. Also, the Groups field is assigned considering the element path provided in its tag.

Go
Edit 
package main

import (
	"encoding/xml"
	"fmt"
)

func main() {
	type Email struct {
		Where string `xml:"where,attr"`
		Addr  string
	}
	type Address struct {
		City, State string
	}
	type Result struct {
		XMLName xml.Name `xml:"Person"`
		Name    string   `xml:"FullName"`
		Phone   string
		Email   []Email
		Groups  []string `xml:"Group>Value"`
		Address
	}
	v := Result{Name: "none", Phone: "none"}

	data := `
		<Person>
			<FullName>Grace R. Emlin</FullName>
			<Company>Example Inc.</Company>
			<Email where="home">
				<Addr>gre@example.com</Addr>
			</Email>
			<Email where='work'>
				<Addr>gre@work.com</Addr>
			</Email>
			<Group>
				<Value>Friends</Value>
				<Value>Squash</Value>
			</Group>
			<City>Hanga Roa</City>
			<State>Easter Island</State>
		</Person>
	`
	err := xml.Unmarshal([]byte(data), &v)
	if err != nil {
		fmt.Printf("error: %v", err)
		return
	}
	fmt.Printf("XMLName: %#v\n", v.XMLName)
	fmt.Printf("Name: %q\n", v.Name)
	fmt.Printf("Phone: %q\n", v.Phone)
	fmt.Printf("Email: %v\n", v.Email)
	fmt.Printf("Groups: %v\n", v.Groups)
	fmt.Printf("Address: %v\n", v.Address)
}