ParseFile in Go

Posted by GoDoc
Public (Editable by Users)

ParseFile parses the source code of a single Go source file and returns the corresponding ast.File node. The source code may be provided via the filename of the source file, or via the src parameter.

Go
Edit 
package main

import (
	"fmt"
	"go/parser"
	"go/token"
)

func main() {
	fset := token.NewFileSet() // positions are relative to fset

	src := `package foo

import (
	"fmt"
	"time"
)

func bar() {
	fmt.Println(time.Now())
}`

	// Parse src but stop after processing the imports.
	f, err := parser.ParseFile(fset, "", src, parser.ImportsOnly)
	if err != nil {
		fmt.Println(err)
		return
	}

	// Print the imports from the file's AST.
	for _, s := range f.Imports {
		fmt.Println(s.Path.Value)
	}
}