FormatInt in Go

Posted by GoDoc
Public (Editable by Users)

FormatInt returns the string representation of i in the given base, for 2 <= base <= 36. The result uses the lower-case letters 'a' to 'z' for digit values >= 10.

Go
Edit 
package main

import (
	"fmt"
	"strconv"
)

func main() {
	v := int64(-42)

	s10 := strconv.FormatInt(v, 10)
	fmt.Printf("%T, %v\n", s10, s10)

	s16 := strconv.FormatInt(v, 16)
	fmt.Printf("%T, %v\n", s16, s16)
}