ParseFloat in Go

Posted by GoDoc
Public (Editable by Users)

ParseFloat converts the string s to a floating-point number with the precision specified by bitSize: 32 for float32, or 64 for float64. When bitSize=32, the result still has type float64, but it will be convertible to float32 without changing its value.

Go
Edit 
package main

import (
	"fmt"
	"strconv"
)

func main() {
	v := "3.1415926535"
	if s, err := strconv.ParseFloat(v, 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat(v, 64); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("NaN", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	// ParseFloat is case insensitive
	if s, err := strconv.ParseFloat("nan", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("inf", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("+Inf", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("-Inf", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("-0", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
	if s, err := strconv.ParseFloat("+0", 32); err == nil {
		fmt.Printf("%T, %v\n", s, s)
	}
}