Duration.String in Go

Posted by GoDoc
Public (Editable by Users)

String returns a string representing the duration in the form "72h3m0.5s". Leading zero units are omitted. As a special case, durations less than one second format use a smaller unit (milli-, micro-, or nanoseconds) to ensure that the leading digit is non-zero. The zero duration formats as 0s.

Go
Edit 
package main

import (
	"fmt"
	"time"
)

func main() {
	t1 := time.Date(2016, time.August, 15, 0, 0, 0, 0, time.UTC)
	t2 := time.Date(2017, time.February, 16, 0, 0, 0, 0, time.UTC)
	fmt.Println(t2.Sub(t1).String())
}